How to arrange even first and odd after in array with Node.js

1 Answer

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function ArrangeEvenOdd(arr) {
    let left = 0;
    let right = arr.length - 1;
    
    while (left < right) {
        if ((arr[left] % 2) != 0) { // odd
            while ((arr[right] % 2 == 1) && right > left) {
                right--;
            }
            let tmp = arr[left];
            arr[left++] = arr[right];
            arr[right--] = tmp;
        }
        else { // even
            left++;
        }
    }
}
        
const arr = [3, 4, 7, 2, 9, 4, 8, 5, 6];
        
ArrangeEvenOdd(arr);

console.log(arr);





/*
run:

[ 6, 4, 8, 2, 4, 9, 7, 5, 3 ]

*/

 



answered Aug 28, 2022 by avibootz

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