How to find minimum distance between two numbers in an array with TypeScript

1 Answer

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function MinDistance(arr : any, number1 : number, number2 : number) {
    const size = arr.length;
    let min_distance = Number.MAX_VALUE;
     
    for (let i = 0; i < size; i++) {
        for (let j = i + 1; j < size; j++) {
            if (arr[i] == number1 && arr[j] == number2 || 
                arr[i] == number2 && arr[j] == number1) {
                min_distance = Math.min(min_distance, Math.abs(i - j));
            }
        }
    }
    return min_distance;
}
         
const arr : number[] = [2, 3, 7, 3, 3, 4, 8, 8, 8, 11, 9, 1, 3];
         
console.log(MinDistance(arr, 3, 8));
 
 
 
 
/*
run:
 
2
 
*/

 



answered Aug 25, 2022 by avibootz

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