Question

How to print all distinct 4 elements from an array that have the same given sum in TypeScript

Answer 1

function getDistinct4Elements(arr : any, sum : number) {
	arr.sort(function(a : number, b : number) {return a - b;});
    const size = arr.length;
    
    for (let i = 0; i <= size - 4; i++) {
        for (let j = i + 1; j <= size - 3; j++) {
         	const k = sum - (arr[i] + arr[j]);
            let fromstart = j + 1;
            let fromend = size - 1;
            while (fromstart < fromend) {
                if (arr[fromstart] + arr[fromend] < k) {
                    fromstart++;
                }
                else if (arr[fromstart] + arr[fromend] > k) {
                        fromend--;
                    }
                    else {
                        console.log(arr[i] + " " + arr[j] + " " + arr[fromstart] + " " + arr[fromend]);
                        fromstart++;
                        fromend--;
                    }
            }
        }
    }
}

const arr:number[] = [4, 8, 1, 5, 9, 0, 3, 7];
        
const sum = 18;

getDistinct4Elements(arr, sum);


  
  
  
  
/*
run:
  
"0 1 8 9"
"0 3 7 8"
"0 4 5 9"
"1 3 5 9"
"1 4 5 8"
  
*/

 

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