How to check if an array contain consecutive integers in TypeScript

1 Answer

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function array_contain_consecutive_integers(arr : any) {
		if (arr.length <= 1) {
        return true;
    }
 
    let min = arr[0];
    let max = arr[0];
        
    for (const val of arr) {
        if (val < min) {
            min = val;
        }
        if (val > max) {
            max = val;
        }
    }
        
    if (max - min != arr.length - 1) {
        return false;
    }
        
    let st = new Set();
    for (const  val of arr) {
        if (st.has(val)) {
            return false;
        }
        st.add(val);
    }
    return true;
}
        
const arr = [-2, 3, 5, 0, -1, 4, 2, 1];

if (array_contain_consecutive_integers(arr)) {
    console.log("Yes");
}
else {
    console.log("No");
}

  
  
  
  
/*
run:
  
"Yes"
  
*/

 



answered Aug 19, 2022 by avibootz

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