Question

How to find the minimum index of a repeating element in a list with Python

Answer 1

def findMininimumIndex(lst):
    minIndex = -1
 
    st = set()
 
    for i in reversed(range(len(lst))):
        if lst[i] in st:
            minIndex = i
        else:
            st.add(lst[i])
 
    return minIndex
 
 
lst = [3, 7, 8, 6, 9, 1, 8, 8, 6, 1, 1, 8]
        
print(findMininimumIndex(lst))



'''
run:

2

'''

 

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