Question

How to parse URL into components in Python

Answer 1

from urllib.parse import urlparse
 
url = 'https://seek4info.com/search.php?query=python'
 
parsed = urlparse(url)

print(parsed)  
 
print(parsed.scheme)  
print(parsed.netloc)  
print(parsed.path)   
print(parsed.params)   
print(parsed.query)   
print(parsed.fragment)   

print(parsed.hostname)  
print(parsed.port)  
 
 
 
 
 
'''
run:
 
ParseResult(scheme='https', netloc='seek4info.com', path='/search.php', params='', query='query=python', fragment='')
https
seek4info.com
/search.php

query=python

seek4info.com
None
 
'''

 

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