How to call inner function inside outer function from outer function in Node.js

1 Answer

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function outerFunc(a, b) {
    console.log("outerFunc");
    function innerFunc(a, b) {
        console.log("innerFunc")
        return a + b;
    }
 
    console.log("result");
    const result = innerFunc(a, b);
 
    return result;
}
 
console.log(outerFunc(13, 24)); 
   

   
   
   
/*
run:
  
outerFunc
result
innerFunc
37

*/

 



answered May 2, 2022 by avibootz
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