Question

How to calculate the series 1 2 3 6 9 18 27 54 81 162 243 ... N in C

Answer 1

// 1 2 3 6 9 18 27 54 81 162 243 ... N 
 
// (1) (2) 1 * 3 (3) 2 * 3 (6) : 3 * 3 (9) 6 * 3 (18) :
// 9 * 3 (27) 18 * 3 (54) : 27 * 3 (81) 54 * 3 (162) :
// 81 * 3 (243)
 
#include <stdio.h>
 
int main()
{
    int a = 1, b = 2, total = 11;
     
    printf("%d %d ", a, b);
     
    for (int i = 3; i <= total; i++) {
        if (i % 2 == 1) {
            a = a * 3;
            printf("%d ", a);
        }
        else {
            b = b * 3;
            printf("%d ", b);
        }
    }
     
    return 0;
}
 
 

 
/*
run:
 
1 2 3 6 9 18 27 54 81 162 243 
 
*/

 

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Answer 2

// 1 2 3 6 9 18 27 54 81 162 243 ... N 

// (1) 1 + 1 (2) : 1 + 2 (3) : 3 + 3 (6) : 3 + 6 (9) :
// 9 + 9 (18) : 9 + 18 (27) : 27 + 27 (54) : 27 + 54 (81) :
// 81 + 81 (162) : 81 + 162 (243)

#include <stdio.h>

int main()
{
    int a = 1, b = 0, total = 11;

    for (int i = 1; i <= total; i++) {
        if (i % 2 == 1) {
            b = a + a;
            printf("%d ", a);
        }
        else {
            a = a + b;
            printf("%d ", b);
        }
    }

    return 0;
}




/*
run:

1 2 3 6 9 18 27 54 81 162 243 

*/

 

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