Question

How to calculate the series (1^1) + (2^2) + (3^3) + (4^4) + ... + (N^N) in JavaScript

Answer 1

const N = 4;
let sum = 0;
 
for (let i = 1; i <= N; i++) {
     let pw = Math.pow(i, i);
     console.log(pw + " + ");
     sum = sum + pw;
}
 
console.log(" = " + sum);

  
  
  
  
/*
run:
  
"1 + "
"4 + "
"27 + "
"256 + "
" = 288"
  
*/

 

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