How to calculate the series (1^1) + (2^2) + (3^3) + (4^4) + ... + (N^N) in C#

1 Answer

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using System;

class Program
{
    static void Main() {
        int N = 4, sum = 0;
  
        for (int i = 1; i <= N; i++) {
            int pw = (int)Math.Pow(i, i);
            Console.Write(pw + " + ");
            sum = sum + pw;
        }
  
        Console.Write("= " + sum);
    }
}




/*
run:
  
1 + 4 + 27 + 256 + = 288
  
*/

 



answered Mar 28, 2022 by avibootz
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