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How to show current date in format ddd yyyy-mm-dd hh:mm:ss zzz in C

1 Answer

0 votes
#include <stdio.h>
#include <time.h>
 
int main(void)
{
    time_t now;
    time(&now);
 
    struct tm tms = *localtime(&now);
    
    // Format: ddd yyyy-mm-dd hh:mm:ss zzz
    char buf[64];
    strftime(buf, sizeof(buf), "%a %Y-%m-%d %H:%M:%S %Z", &tms);
     
    printf("%s", buf);
     
    return 0;
}
 
 
 
/*
run:
 
Fri 2022-03-25 08:30:04 UTC
 
*/

 



answered Mar 25, 2022 by avibootz
edited Mar 25, 2022 by avibootz

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