Question

How to use isfinite() function to check if the given floating point number has finite value in C

Answer 1

#include <stdio.h>     
#include <math.h>
 
int main(int argc, char **argv)
{	
	printf("isfinite(NAN) = %d\n", isfinite(NAN));
    printf("isfinite(INFINITY) = %d\n", isfinite(INFINITY));
    printf("isfinite(0.0) = %d\n", isfinite(0.0));
	printf("isfinite(1.0 / 0.0) = %d\n", isfinite(1.0 / 0.0));
    printf("isfinite(0.0 / 2.0) = %d\n", isfinite(0.0 / 2.0));
    printf("isfinite(1.0) = %d\n", isfinite(1.0));
	printf("isfinite(-1.0 / 0.0) = %d\n",isfinite(-1.0 / 0.0));
	
    return 0;
}

// non-zero value if x is finite, zero otherwise

/*
run:
  
isfinite(NAN) = 0
isfinite(INFINITY) = 0
isfinite(0.0) = 1
isfinite(1.0 / 0.0) = 0
isfinite(0.0 / 2.0) = 1
isfinite(1.0) = 1
isfinite(-1.0 / 0.0) = 0

*/

 

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