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How to use cal_from_jd() function to convert a julian day count into a date in PHP



176 views
asked Mar 10, 2016 by avibootz
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1 Answer

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$today = unixtojd(mktime(0, 0, 0, 3, 10, 2016));
echo "<pre>";
print_r(cal_from_jd($today, CAL_GREGORIAN));
echo "</pre>";


/*
run:

Array
(
    [date] => 3/10/2016
    [month] => 3
    [day] => 10
    [year] => 2016
    [dow] => 4
    [abbrevdayname] => Thu
    [dayname] => Thursday
    [abbrevmonth] => Mar
    [monthname] => March
)
   
*/

 



answered Mar 10, 2016 by avibootz

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