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How to find the nearest smaller element on left side of each element of an array in C

1 Answer

0 votes
#include <stdio.h>
 
int smaller_index(int arr[], int pos) {
    int index = -1;
 
    for (int i = pos - 1; i >= 0 && index==-1; i--) {
        if (arr[i] < arr[pos]) {
            index = i;
        }
    }
    return index;
}
void nearest_smaller(int arr[], int size) {
    int index = 0;
 
    for (int i = 0; i < size; i++) {
        index = smaller_index(arr, i);
 
        if (index == -1) {
            printf("%d : No Smaller\n", arr[i] );
        }
        else  {
            printf("%d : %d\n",arr[i], arr[index]);
        }
    }
}
 
int main()
{
  int arr[] = {4, 6, 2, 8, 6, 1, 9, 12, 3, 20, 18, 30};
 
  int size = sizeof(arr) / sizeof(arr[0]);
 
  nearest_smaller(arr, size);
   
  return 0;
}
 
 
 
 
/*
run:
 
4 : No Smaller
6 : 4
2 : No Smaller
8 : 2
6 : 2
1 : No Smaller
9 : 1
12 : 9
3 : 1
20 : 3
18 : 3
30 : 18
 
*/

 



answered Dec 19, 2021 by avibootz
edited Dec 19, 2021 by avibootz
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