How to print a list when first element is first max and second element is first min and so on in C#

1 Answer

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using System;

class Program
{
    static void print_first_max_second_min(int[] arr) { 
        Array.Sort(arr); 
  
        int size = arr.Length;  
        int i = 0, j = size - 1; 
        while (i < j) { 
            Console.Write(arr[j--] + " "); 
            Console.Write(arr[i++] + " "); 
        } 

        if (size % 2 != 0) 
            Console.WriteLine(arr[i]); 
    } 
    static void Main() {
        int[] arr = {13, 5, 2, 10, 4, 9, 7, 8, 559}; 

        print_first_max_second_min(arr); 
    }
}

 
 
 
/*
run:
 
559 2 13 4 10 5 9 7 8
     
*/

 



answered Dec 8, 2021 by avibootz
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