Question

How to check if array contains only distinct (non-repeating) elements in JavaScript

Answer 1

function containsOnlyUniqueElement(arr) {
    const size = arr.length;
    let set = new Set();
     
    for (let i = 0; i < size; i++) {
        set.add(arr[i]);
    }
     
    if (set.size == size) {
        return true;
    }
    else {
        return false;
    }
}
 

const arr = [1, 5, 7, 3, 9, 8, 0, 2];
 
if (containsOnlyUniqueElement(arr)) {
    console.log("Yes");
}
else {
    console.log("No");
}
  
  
  
  
  
/*
run:
    
"Yes"
    
*/

 

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Answer 2

function containsOnlyUniqueElement(arr) {
    const set = new Set(arr);

    return set.size === arr.length;
}
 

const arr = [1, 5, 7, 3, 9, 8, 0, 2];
 
if (containsOnlyUniqueElement(arr)) {
    console.log("Yes");
}
else {
    console.log("No");
}
  
  
  
  
  
/*
run:
    
"Yes"
    
*/

 

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