Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,941 questions

51,879 answers

573 users

How to reorder an array according to given indexes in Java

1 Answer

0 votes
public class MyClass {
    public static void print(int arr[]) {
        int size = arr.length;
        
        for (int i = 0; i < size; i++) {
            System.out.print(arr[i] + " ");
        }
        System.out.println();
    }

    public static void reorder(int arr[], int indexes[], int i) {
        int size = arr.length;
        
        if (i < size) {
            int data = arr[i];
    
            reorder(arr, indexes, i+1);
    
            arr[indexes[i]] = data;
        }
    }
    public static void main(String args[]) {
        int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
        int indexes[] = {1, 0, 4, 3, 2, 5, 9, 7, 8, 6};
     
        print(arr);
        print(indexes);
        
        reorder(arr, indexes ,0);
        
        print(arr);
    }
}



/*
run:
     
1 2 3 4 5 6 7 8 9 10 
1 0 4 3 2 5 9 7 8 6 
2 1 5 4 3 6 10 8 9 7 
     
*/

 



answered Nov 28, 2021 by avibootz
edited Nov 28, 2021 by avibootz

Related questions

1 answer 255 views
1 answer 175 views
1 answer 193 views
1 answer 184 views
1 answer 216 views
1 answer 181 views
1 answer 224 views
...