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How to reorder an array according to given indexes in Java

1 Answer

0 votes
public class MyClass {
    public static void print(int arr[]) {
        int size = arr.length;
        
        for (int i = 0; i < size; i++) {
            System.out.print(arr[i] + " ");
        }
        System.out.println();
    }

    public static void reorder(int arr[], int indexes[], int i) {
        int size = arr.length;
        
        if (i < size) {
            int data = arr[i];
    
            reorder(arr, indexes, i+1);
    
            arr[indexes[i]] = data;
        }
    }
    public static void main(String args[]) {
        int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
        int indexes[] = {1, 0, 4, 3, 2, 5, 9, 7, 8, 6};
     
        print(arr);
        print(indexes);
        
        reorder(arr, indexes ,0);
        
        print(arr);
    }
}



/*
run:
     
1 2 3 4 5 6 7 8 9 10 
1 0 4 3 2 5 9 7 8 6 
2 1 5 4 3 6 10 8 9 7 
     
*/

 



answered Nov 28, 2021 by avibootz
edited Nov 28, 2021 by avibootz

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