Question

How to map array of a number to the corresponding alphabet (1-a 2-b ... 26-z) in C

Answer 1

#include <stdio.h>
 
int main(void) {
    int arr[] = {1, 12, 7, 26, 18, 20};
  
    int size = sizeof(arr)/sizeof(arr[0]); 
    for (int i = 0; i < size; i++) {
        printf("%c ", arr[i] + 'a' - 1);  // -1 for 'a' // 1-'a' ... 26-'a'
    }
}
 
 
 
/*
run:
  
a l g z r t 
  
*/

 

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Answer 2

#include <stdio.h>
 
int main(void) {
    char abc[] = "abcdefghijklmnopqrstuvwxyz";
     
    int arr[] = {1, 12, 7, 26, 18, 20};
  
    int size = sizeof(arr)/sizeof(arr[0]); 
    for (int i = 0; i < size; i++) {
        printf("%c ", abc[arr[i] - 1]);  // -1 for 'a' // 1-'a' ... 26-'a'
    }
}
 
 
 
/*
run:
  
a l g z r t 
  
*/

 

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