Question

How to segregate even and odd numbers of an array (even on left and odd on right) in Ruby

Answer 1

def segregateElement(arr) 
	size = arr.length
	j = 0
	i = 0
	while (i < size) 
		if (arr[i] % 2 == 0) 
			arr[i], arr[j] = arr[j], arr[i]
			j += 1
		end

		i += 1
	end
end

def main() 
	arr = [1, 8, 7, 3, 9, 4, 2, 5, 10]

	size = arr.length

	segregateElement(arr)
	
	print(arr)
end

main()


 
#
# run:
# 
# [8, 4, 2, 10, 9, 1, 7, 5, 3]
#

 

70+ SQL courses for beginners and professionals