// If the sum of all factors of a number is equal to the number, then the number is perfect
// 6
// factors = 1, 2, 3
// 1 + 2 + 3 = 6
using System;
class Program
{
static void Main() {
int num = 6;
int sumOfFactors = 0;
for (int i = 1; i < num; i++)
if (num % i == 0)
sumOfFactors += i;
if (sumOfFactors == num)
Console.Write("Perfect Number");
else
Console.Write("Not a Perfect Number");
}
}
/*
run:
Perfect Number
*/