Question

How to declare, initialize and print two-dimensional (2D) list (array) of integers in Python

Answer 1

from sys import stdout


def print_list(list2d, n):
    for ii in range(n):
        for jj in range(n):
            stdout.write("%4d" % list2d[ii][jj])
        stdout.write("\n")


a = [[1, 8, 5], [6, 7, 1], [8, 7, 6]]
size = 3

print_list(a, size)

'''
run:

   1   8   5
   6   7   1
   8   7   6

'''

 

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Answer 2

from sys import stdout
import random


def print_list(list2d, n):
    for ii in range(n):
        for jj in range(n):
            stdout.write("%4d" % list2d[ii][jj])
        stdout.write("\n")


def init_list(list2d, n):
    for ii in range(n):
        for jj in range(n):
            list2d[ii][jj] = random.randint(2, 9)


a = [[0 for x in range(3)] for x in range(3)]
size = 3

print_list(a, size)
init_list(a, size)
print()
print_list(a, size)

'''
run:

   0   0   0
   0   0   0
   0   0   0

   8   2   2
   7   5   8
   6   3   7

'''

 

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Answer 3

from sys import stdout
import random


def print_list(list2d):
    for ii in range(len(list2d)):  # rows
        for jj in range(len(list2d[0])):  # columns
            stdout.write("%4d" % list2d[ii][jj])
        stdout.write("\n")


def init_list(list2d):
    for ii in range(len(list2d)):  # rows
        for jj in range(len(list2d[0])):  # columns
            list2d[ii][jj] = random.randint(2, 9)


a = [[0 for x in range(3)] for x in range(2)]

print_list(a)
init_list(a)
print()
print_list(a)

'''
run:

   0   0   0
   0   0   0

   7   5   8
   9   7   6

'''

 

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