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How to declare, initialize and print two dimensional (2D) int array in C#

3 Answers

0 votes
using System;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            int[,] a = new int[3, 3] { { 1, 8, 5 }, { 6, 7, 1 }, { 8, 7, 6 } };

            Print(a);
        }
        static void Print(int[,] arr2d)
        {
            for (int i = 0; i < arr2d.GetLength(0); i++)
            {
                for (int j = 0; j < arr2d.GetLength(1); j++)
                    Console.Write("{0, 4}", arr2d[i, j]);
                Console.WriteLine();
            }
        }
    }
}


/*
run:
    
   1   8   5
   6   7   1
   8   7   6

*/

 



answered Mar 1, 2016 by avibootz
0 votes
using System;

namespace ConsoleApplication_C_Sharp
{
    class Program
    {
        static void Main(string[] args)
        {
            int[,] a = new int[,] { { 1, 2 }, { 3, 4 }, { 5, 6 } };

            Print(a);
        }
        static void Print(int[,] arr2d)
        {
            for (int i = 0; i < arr2d.GetLength(0); i++)
            {
                for (int j = 0; j < arr2d.GetLength(1); j++)
                    Console.Write("{0, 4}", arr2d[i, j]);
                Console.WriteLine();
            }
        }
    }
}


/*
run:
    
   1   2
   3   4
   5   6

*/

 



answered Mar 1, 2016 by avibootz
0 votes
using System;

namespace ConsoleApplication_C_Sharp
{
    class Program
    {
        static void Main(string[] args)
        {
            int[,] a = new int[2, 3];

            initArray(a);
            Print(a);
        }
        static void Print(int[,] arr2d)
        {
            for (int i = 0; i < arr2d.GetLength(0); i++)
            {
                for (int j = 0; j < arr2d.GetLength(1); j++)
                    Console.Write("{0, 4}", arr2d[i, j]);
                Console.WriteLine();
            }
        }
        static void initArray(int[,] arr2d)
        {
            Random rnd = new Random();
            for (int i = 0; i < arr2d.GetLength(0); i++)
                for (int j = 0; j < arr2d.GetLength(1); j++)
                    arr2d[i, j] = rnd.Next(2, 9);
        }

    }
}


/*
run:
    
   8   4   7
   6   3   4

*/

 



answered Mar 1, 2016 by avibootz
...