How to find the next sparse number which greater than or equal to a given number in Ruby

1 Answer

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# If there are no two consecutive 1s in a number binary representation, 
# it is Sparse. 5 (101) is sparse, 6 (110) is not. 
  
class Number 
    def is_sparse(n) 
        result = n & (n >> 1);
             
        if (result == 0)
            return true;
        end
          
        return false;
    end
 
    def next_sparse(number) 
        while (true) 
          if (self.is_sparse(number)) 
            return number
          end
          number += 1
        end
    end
end   
  
def main() 
  obj = Number.new()
    
  puts obj.next_sparse(6)
  puts obj.next_sparse(5)
  puts obj.next_sparse(38)
  puts obj.next_sparse(305)
end
  
main()
  
  
  
  
# run:
#
# 8
# 5
# 40
# 320
#

 



answered Oct 12, 2021 by avibootz
edited Oct 16, 2021 by avibootz
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