How to swap two arrays without using temporary variable in C

1 Answer

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#include <stdio.h>

int main(void) {
    int first[5] = {1, 2, 3, 4, 5} , second[] = {99, 88, 77, 66, 55};
    int size = sizeof(first)/sizeof(first[0]);
    
    for (int i = 0; i < size; i++) {
        first[i] = first[i] + second[i];
        second[i] = first[i] - second[i];
        first[i] = first[i] - second[i];
    }
   
    printf("First\n");
    for (int i = 0; i < size; i ++) {
        printf("%d ",first[i]);
    }
   
    printf("\nSecond\n");
    for (int i = 0; i < size; i ++) {
        printf("%d ",second[i]);
    }
   
    return 0;
}





/*
run:

First
99 88 77 66 55 
Second
1 2 3 4 5 

*/

 



answered Oct 8, 2021 by avibootz

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