Question

How to count the total number of punctuation characters in a string with C

Answer 1

#include <stdio.h>
#include <string.h>

int main(void) {
    char str[] = "C is a general-purpose, procedural computer programming language.";    
    int count = 0;  

    for (int i = 0; i < strlen(str); i++) {  
        if (str[i] == '-' || str[i] == ',' || str[i] == ';' || str[i] == '.' || str[i] == ':' ||   
            str[i] == '!' || str[i] == '\'' || str[i] == '\"' || str[i] == '?') {  
                count++;  
        }  
    }  
    printf("%d", count);  

    return 0;
}





/*
run:

3

*/

 

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