Question

How to print all disarium numbers between 1 and 100 in C++

Answer 1

#include <iostream>
#include <cmath>
 
// if (sum of number digit raised to the power of their respective position) == (number))
//     std::cout << "disarium number";
 
int sumDigits(int num) {
    int remainder = 0;
    int len = log10(num) + 1;
    float sum = 0.0f;
 
    int temp = num;
    while (temp > 0) {
        remainder = temp % 10;
        sum = sum + pow((double)remainder, (double)len);
        temp = temp / 10;
        len--;
    }
 
    return sum;
}
 
int main()
{
    for (int i = 1; i <= 100; i++) {
        if (i == sumDigits(i))
            std::cout << i << " ";
    }
 
    return 0;
}
 
 
 
/*
run:
 
1 2 3 4 5 6 7 8 9 89

*/

 

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