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How to check whether all numbers in array are odd or not in JavaScript



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asked Jun 12, 2021 by avibootz
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1 Answer

0 votes 
const numbers = [1,3,5,7,9,11,13];

console.log(numbers.every(number => number % 2 === 1))

  
    
    
/*
run:
    
true
    
*/

 



answered Jun 12, 2021 by avibootz

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