How to increment and decrement variable in Bash

3 Answers

0 votes
i=12

i=$((i+1))

echo $i

i=$((i-3))

echo $i  
  

  
  
# run:
#
# 13
# 10
#

 



answered May 26, 2021 by avibootz
0 votes
i=12

((i=i+1))

echo $i

((i=i-3))

echo $i  
  

  
  
# run:
#
# 13
# 10
#

 



answered May 26, 2021 by avibootz
0 votes
i=12
 
((i+=1))
 
echo $i
 
((i-=3))
 
echo $i  
   
 
   
   
# run:
#
# 13
# 10
#

 



answered May 26, 2021 by avibootz

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