Question

How to initialize 2D char array in C

Answer 1

#include <stdio.h>

int main(){
    char arr[][4] = { "abcd", "efgh", "ijkl" };

    int rows = sizeof(arr)/sizeof(arr[0]);

    for (size_t i = 0; i < rows; i++) {
        for (size_t j = 0; j < 4; j++) {
            printf("%c ", arr[i][j]);
        }
        printf("\n");
    }

    return 0;
}




/*
run:

a b c d
e f g h
i j k l

*/

 

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Answer 2

#include <stdio.h>
#include <string.h>

int main(){
    const char *arr[3] = { "ab", "efg", "ijkl" };

    for (size_t i = 0; i < 3; i++) {
        for (size_t j = 0; j < strlen(arr[i]); j++) {
            printf("%c ", arr[i][j]);
        }
        printf("\n");
    }

    return 0;
}




/*
run:

a b
e f g
i j k l

*/

 

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