Question

How to implement a function that truncate float in Python

Answer 1

def truncate(f, n):
    i = int(f * (10**n)) / (10**n)
    
    return float(i)
    
print(truncate(4478.123789, 4))
print(truncate(127.50, 4))
print(truncate(127.51, 4))


    
    

'''
run:

4478.1237
127.5
127.51

'''

 

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Answer 2

def truncate(f, n):
    s = str(f)
    for i in range(len(s)):
        if s[i] == '.':
            try:
                return float(s[:i + n + 1])
            except:
                return float(s)      
    return float(s)
    
print(truncate(4478.123789, 4))
print(truncate(127.50, 4))
print(truncate(127.51, 4))


    
    

'''
run:

4478.1237
127.5
127.51

'''

 

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