How to break out of multiple loops in Python

1 Answer

0 votes
def search_list(n):
    for i in range(3):
        for j in range(3):
            if lst[i][j] == n:
                return True
  
    return False
    
    
lst = [ [1,2,3],
        [4,5,6],
        [7,8,9] ]    

print(search_list(3))

print(search_list(50))




'''
run:

True
False

'''

 



answered Apr 24, 2021 by avibootz

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