Question

How to get the length of one dimensional int array (array[]) in C

Answer 1

#include <stdio.h>
 
int main(void)
{
    int n[] = { 1, 2, 3, 4, 5 };
 
	printf("int size: %d\n", (int)sizeof(int));
	printf("Total size: %d\n", (int)sizeof(n));
    printf("n[0] size: %d\n", (int)sizeof(n[0]));
    printf("Array size: %d\n", (int)(sizeof(n)/sizeof(n[0])));
     
    return 0;
}
 
  
/*
    
run:
    
int size: 4
Total size: 20 // 4 x 5
n[0] size: 4
Array size: 5

*/

 

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Answer 2

#include <stdio.h>
 
int main(void)
{
    char arr[] = { 'a', 'b', 'c', 'd', 'e' };
 
	printf("char size: %d\n", (int)sizeof(char));
	printf("Total size: %d\n", (int)sizeof(arr));
    printf("arr[0] size: %d\n", (int)sizeof(arr[0]));
    printf("Array size: %d\n", (int)(sizeof(arr)/sizeof(arr[0])));
     
    return 0;
}
 
  
/*
    
run:
    
char size: 1
Total size: 5
arr[0] size: 1
Array size: 5

*/

 

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