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How to use \s regular expression (REGEX) in Java

1 Answer

0 votes
import java.util.regex.Matcher;
import java.util.regex.Pattern;
    
public class Example {
    private static void searchREGEX(String regex, String... search) {
        Pattern pattern = Pattern.compile(regex);
        
        for (String input : search) {
            Matcher matcher = pattern.matcher(input);
   
            boolean found = false;
            
            while (matcher.find()) {
                System.out.println(String.format("Found" + " \"%s\" " + "from index %d to %d",
                                            matcher.group(), matcher.start(), matcher.end()));
                found = true;
            }
            
            System.out.println();
            
            if (!found) {
                 System.out.println(String.format("%s: \"%s\" Not found\n", regex, input));
            }
        }
    }  
    public static void main(String[] args) {
        // \s   (A whitespace character: [ \t\n\x0B\f\r])
        searchREGEX("\\s", " ", "1", "f35\\n", ".", "0\\r12", "\t");
    }
    
}
    
    
    
/*
run:
     
Found " " from index 0 to 1
 
 
\s: "1" Not found
 
 
\s: "f35\n" Not found
 
 
\s: "." Not found
 
 
\s: "0\r12" Not found
 
Found " " from index 0 to 1
     
*/

 



answered Jan 22, 2016 by avibootz
edited May 14, 2024 by avibootz

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