How to find highest frequency character in a string with Java

1 Answer

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public class MyClass {
    static final int TOTLAASCII = 256; 
    
    public static void main(String args[]) {
        String s = "javac++phpcpythonc#";
        char arr[] = new char[TOTLAASCII]; 
        int len = s.length(); 
     
        for (int i = 0; i < len; i++) {
            arr[s.charAt(i)]++;
        }
     
        int max = arr[0];
        char ch = ' ';
        for (int i = 1; i < TOTLAASCII; i++) {
            if (arr[i] > 0) {
               System.out.println((char)i + " - " + (int)arr[i]);
                if (arr[i] > max) {
                    max = arr[i];
                    ch = (char)i;
                }
            }
        }
        System.out.println("Highest frequency character: " + ch);
    }
}




/*
run:

# - 1
+ - 2
a - 2
c - 3
h - 2
j - 1
n - 1
o - 1
p - 3
t - 1
v - 1
y - 1
Highest frequency character: c

*/

 



answered Jan 20, 2021 by avibootz

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