How to dynamically allocate array in C

1 Answer

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#include <stdio.h>
#include <stdlib.h>

#define SIZE 12

int main() {
    int *arr = calloc(SIZE, sizeof(int));
    
    if (arr == NULL) {
        fprintf(stderr, "calloc error");
        return 1;
    }
    
    arr[1] = 234;
    arr[3] = 9713;
    arr[7] = 18;
    
    for (int i = 0; i < SIZE; i++)
         printf("%d ", arr[i]);
    
    free(arr);
    
    return 0;
}
  
  

  
/*
run:
  
0 234 0 9713 0 0 0 18 0 0 0 0 

*/

 



answered Dec 28, 2020 by avibootz
edited Dec 28, 2020 by avibootz

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