How to iterate over an array using pointers in C

1 Answer

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#include <stdio.h>

int main() {
    int arr[] = {6, 8, 12, 9, 0, 3, 5 };
    int size = sizeof(arr)/sizeof(arr[0]);

    for (int *p = &arr[0]; p <= arr + size - 1; p++) {
        printf("%d ", *p);
    }
    
    return 0;
}
 
 
 
/*
run:
 
6 8 12 9 0 3 5 
 
*/

 



answered Dec 26, 2020 by avibootz

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