Question

How to extract the last number from string in VB.NET

Answer 1

Imports System
Imports System.Text.RegularExpressions
				
Public Module Module1
	Public Sub Main()
		Dim s As String = "12abc 9836 xy%^(s 33 * 9 100 200ppp"

		Dim numbers As String() = Regex.Split(s, "\D+")
        
		Dim n As Integer = Integer.Parse(numbers(numbers.Length - 2))

        Console.WriteLine("{0}", n)
	End Sub
End Module




' run:
'
' 200
'

 

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