How to implement interface in Java

1 Answer

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package javaapplication1;

public interface Animal {
 
    public void Showtalent(String talent);
    public void showDetails();
}
package javaapplication1;

public class Dog implements Animal {
    public void Showtalent(String talent) {
        System.out.println("talent: " + talent);
    }
     
    public void showDetails() {
        System.out.println("I'm a dog");
    }
}
package javaapplication1;

public class Bird implements Animal {
    public void Showtalent(String talent) {
        System.out.println("talent: " + talent);
    }
     
    public void showDetails() {
        System.out.println("I'm a bird");
    }
}
package javaapplication1;

public class InterfaceTest {
    public static void main(String[] args) {
	    Animal dog = new Dog();
	    Animal bird = new Bird();
 
	    dog.showDetails();
	    dog.Showtalent("can run");
        
        bird.showDetails();
        bird.Showtalent("can fly");
    }
}

/*
run:

I'm a dog
talent: can run
I'm a bird
talent: can fly

*/

 



answered Jan 7, 2016 by avibootz
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