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How to get the largest integer that is less than or equal to a number (floor) in Groovy



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asked Oct 3, 2020 by avibootz
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1 Answer

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double d = -3.7
System.out.println(Math.floor(d))

d = 3.9
System.out.println(Math.floor(d))

d = 3.4
System.out.println(Math.floor(d)) 




/*
run:

-4.0
3.0
3.0

*/

 



answered Oct 3, 2020 by avibootz
edited Oct 4, 2020 by avibootz

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