How to pass array to function as argument in Go

1 Answer

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package main

import "fmt"

func print(arr [4]int) {
    fmt.Println(arr[0])
    fmt.Println(arr[1])
    fmt.Println(arr[2])
    fmt.Println(arr[3])
}

func main() {
    arr := [...]int{3, 6, 8, 1}

    print(arr)
}
 
 
 
/*
run:
 
3
6
8
1
 
*/

 



answered Sep 4, 2020 by avibootz

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