How to sum elements of deque values in C++

2 Answers

0 votes
#include <iostream> 
#include <deque> 
  
int sumdq(std::deque <int> dq) { 
    int sum = 0;
    while (!dq.empty()) { 
        sum += dq.front(); 
        dq.pop_front(); 
    } 
    return sum;
} 
    
int main() 
{ 
    std::deque<int> dq;
      
    dq.push_back(4); 
    dq.push_back(2); 
    dq.push_back(5); 
    dq.push_back(1); 
    dq.push_back(9); 
    dq.push_back(8);  
   
    std::cout << sumdq(dq);
} 
  
  
  
/*
run:
  
29
  
*/

 



answered Jul 21, 2020 by avibootz
edited Feb 25, 2023 by avibootz
0 votes
#include <iostream> 
#include <deque> 
    
void printdq(std::deque <int> dq) { 
    for (auto &n: dq)
        std::cout << n << ", ";
    std::cout << '\n'; 
} 
 
int sumdq(std::deque <int> dq) { 
    int sum = 0;
    for (auto &n: dq)
        sum += n;
    return sum;
} 
    
int main() 
{ 
    std::deque<int> dq = { 1, 2, 3, 4, 5, 6 }; 
        
    printdq(dq); 
 
    std::cout << '\n' << sumdq(dq); 
} 
      
      
      
/*
run:
      
1, 2, 3, 4, 5, 6, 
 
21
  
*/

 



answered Jul 30, 2020 by avibootz
edited Feb 25, 2023 by avibootz

Related questions

1 answer 103 views
1 answer 175 views
1 answer 178 views
1 answer 137 views
1 answer 236 views
236 views asked Aug 1, 2020 by avibootz
1 answer 157 views
1 answer 180 views
...