How to use shot if in PHP

4 Answers

0 votes
$dirname = "/about.html";
$dirname = ($dirname == "\\" || $dirname == "/") ? "" : $dirname;

echo $dirname . "<br>";




/*
run:

/about.html

*/

 



answered Jul 12, 2020 by avibootz
0 votes
$s = "PHP";

echo empty($s) ? "Empty" : "Not empty";




/*
run:

Not empty

*/

 



answered Jul 12, 2020 by avibootz
0 votes
$s = "";

echo empty($s) ? true : false;




/*
run:

1

*/

 



answered Jul 12, 2020 by avibootz
0 votes
$s = "PHP";

echo $s ?? "Empty...";
echo "<br>";
echo !empty($s) ? $s : 'Empty'; // Equivalent to: echo $s ?? "Empty...";
echo "<br>";

$s = null;
echo $s ?? "Empty...";
echo "<br>";
echo !empty($s) ? $s : 'Empty'; // Equivalent to: echo $s ?? "Empty...";



/*
run:

PHP
PHP
Empty...
Empty

*/

 



answered Jul 12, 2020 by avibootz

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