Question

How to find the second smallest elements in an array in Java

Answer 1

import java.io.*; 

public class MyClass {
    static int getTheSecondSmallest(int arr[]) { 
        int first, second, size = arr.length; 
     
        first = second = Integer.MAX_VALUE; 
        for (int i = 0; i < size ; i ++) { 
            if (arr[i] < first) { 
                second = first; 
                first = arr[i]; 
            } 
            else if (arr[i] < second && arr[i] != first) 
                second = arr[i]; 
        } 
        if (second == Integer.MAX_VALUE) 
            return -1;
             
        return second; 
    } 
    public static void main(String args[]) {
        int arr1[] = {34, 3, 8, 2, 9, 4, 6}; 
        System.out.println(getTheSecondSmallest(arr1));
     
        int arr2[] = {1, 1, 2, 1, 1}; 
        System.out.println(getTheSecondSmallest(arr2));
     
        int arr3[] = {5, 5, 5, 5, 5, 5, 5}; 
        System.out.println(getTheSecondSmallest(arr3));
    }
}



/*
run:

3
2
-1

*/

 

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