Question

How to pass a dynamic amount of keyword arguments to a function in Python

Answer 1

def f(**kwargs):  
  for key, value in kwargs.items(): 
      print("%s == %s" %(key, value)) 
 
     
f(a = 'python', b = 'php', c = 'java')  
print()
f(lang1 = 'python', lang2 = 'php', lang3 = 'java', lang4 = 'c', lang5 = 'c++')  
 
 
   
'''
run:
   
a == python
b == php
c == java
 
lang1 == python
lang2 == php
lang3 == java
lang4 == c
lang5 == c++
          
'''

 

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