Question

How to implement the itoa() function to convert int to string in C

Answer 1

#include <stdio.h>
#include <string.h>
  
#define LEN 10
  
void my_itoa(int n, char s[]);
  
int main(void)
{
    char s[LEN];
    int n = 23479;
      
    my_itoa(n, s);
    printf("s = %s\n", s);
     
    return 0;
}
 
void my_itoa(int n, char s[]) 
{ 
    int i, sign = n; 
     
    if (n < 0) 
        n = -n;         
    i = 0; 
    do
    {     
        s[i++] = n % 10 + '0';  
    } while ( (n /= 10) > 0);   
        
    if (sign < 0) 
        s[i++] = '-'; 
    s[i] = '\0'; 
     
    strrev(s); 
} 
  
/*
run:
    
s = 23479
 
*/

 

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Answer 2

#include <stdio.h>
#include <string.h>
  
#define LEN 13
  
void my_itoa(int n, char s[]);
  
int main(void)
{
    char s[LEN];
    int n = -87423;
      
    my_itoa(n, s);
    printf("s = %s\n", s);
     
    return 0;
}
 
void my_itoa(int n, char s[]) 
{ 
    int i, sign = n; 
     
    if (n < 0) 
        n = -n;         
    i = 0; 
    do
    {     
        s[i++] = n % 10 + '0';  
    } while ( (n /= 10) > 0);   
        
    if (sign < 0) 
        s[i++] = '-'; 
    s[i] = '\0'; 
     
    strrev(s); 
} 
  
/*
run:
    
s = -87423
 
*/

 

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