Question

How to print the distinct elements of an array in Java

Answer 1

public class Program {
    public static void printDistinct(int[] arr) {
        int total;
        for (int i = 0; i < arr.length; i++) {  
            total = 0;
            for (int j = 0; j < arr.length; j++) { 
                if (arr[i] != arr[j])  
                    total++;
            }  
            if (total == arr.length - 1)
                System.out.println(arr[i]);  
        }
    }
    
    public static void main(String args[]) {
        int[] arr = { 3, 5, 9, 1, 7, 8, 1, 9, 0, 3, 9 };
    
        printDistinct(arr);
    }  
}
 
    
    
/*
run:
    
5
7
8
0
    
*/

 

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Answer 2

import java.util.Arrays;
  
public class Program {
    public static void printAllUniqueElements(int [] arr) {
        Arrays.sort(arr);
          
        int current = arr[0];
        System.out.print(current + " ");
         
        for (int i = 1; i <arr.length ; i++) {
            if (current != arr[i]) {
                System.out.print(arr[i] + " ");
                current = arr[i];
            }
        }
    }
    public static void main(String args[]) {
        int[] arr = {1, 4, 8, 8, 8, 1, 1, 1, 1, 7, 9 ,9, 5, 3};
        
        printAllUniqueElements(arr);
     }
}

  
     
/*
run:
            
1 3 4 5 7 8 9 
            
*/
 

 

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Answer 3

import java.util.HashSet;
 
public class Program {
    public static void printAllUniqueElements(int [] arr) {
        HashSet<Integer> hashSet = new HashSet<>();
         
        for (int i = 0; i < arr.length ; i++) {
            if (!hashSet.contains(arr[i])) {
                System.out.print(arr[i] + " ");
                hashSet.add(arr[i]);
            }
        }
    }
    public static void main(String args[]) {
        int[] arr = {1, 4, 8, 8, 8, 1, 1, 1, 1, 7, 9 ,9, 5, 3};
       
        printAllUniqueElements(arr);
    }
}

 
    
/*
run:
           
1 4 8 7 9 5 3 
           
*/

 

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