Question

How to use pointer to array of pointers in C

Answer 1

#include <stdio.h>
  
#define LEN 5

int main ()
{
	int arr[] = {3, 5, 23, 871, 2};  
	int *array_of_pointers[LEN]; 
   
	for (int i = 0; i < LEN; i++) {
		array_of_pointers[i] = &arr[i];    
	}	
	
	int **pp  = array_of_pointers;
   
	for (int i = 0; i < LEN; i++) {
		printf("arr[%d] = %d\n", i, *pp[i]);
	}
   
	return 0;
}





/*
run:

arr[0] = 3
arr[1] = 5
arr[2] = 23
arr[3] = 871
arr[4] = 2

*/

 

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Answer 2

#include <stdio.h>
  
#define LEN 5

int main ()
{
	int arr[] = {3, 5, 23, 871, 2};  
	int *array_of_pointers[LEN]; 
   
	for (int i = 0; i < LEN; i++) {
		array_of_pointers[i] = &arr[i];    
	}	
	
	int* (*pp)[LEN] = &array_of_pointers;
   
	for (int i = 0; i < LEN; i++) {
		printf("arr[%d] = %d\n", i, *(*pp)[i]);
	}
   
	return 0;
}





/*
run:

arr[0] = 3
arr[1] = 5
arr[2] = 23
arr[3] = 871
arr[4] = 2

*/

 

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