How to convert part of a string to uppercase start from specific index in Java

1 Answer

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public class MyClass {
    public static String convert_part_to_uppercase(String s, int idx) { 
        if (idx < 0 || idx > s.length()) return s;
           
        String tmp = "";
        for (int i = 0; i < s.length(); i++) {
            if (i >= idx && (s.charAt(i) >= 97 && s.charAt(i) <= 122)) {
                char ch = s.charAt(i);
                tmp += Character.toUpperCase(ch);
            }
            else {
                tmp += s.charAt(i); 
            }
        }
               
        return tmp;
    }
    public static void main(String args[]) {
        String s = "java programming";
 
        s = convert_part_to_uppercase(s, 3);
 
        System.out.println(s);
    }
}
 
 
 
 
/*
run:
 
javA PROGRAMMING
 
*/

 



answered Nov 12, 2019 by avibootz
edited Nov 16, 2019 by avibootz
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