Question

How to check if a given string is a valid BigInteger in Java

Answer 1

import java.math.BigInteger;

public class MyClass {
    public static void main(String args[]) {
        String s1 = "8217528938039999999999982734590087211199382724324131999999999372732342342928727231421289"; 
        String s2 = "99999999999999999999999289380398273459009393837372827846462323998923842908472984729839199999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999990982374121"; 
        String s3 = "821752893803999999999998273459008721119938272432413e500"; 
        
        try 
        { 
            new BigInteger(s1); 
            System.out.println(s1 + " is a valid BigInteger"); 
        }  
        catch (NumberFormatException e)  
        { 
            System.out.println(s1 + " is not a valid BigInteger"); 
            System.out.println(e);
        } 
          
        try 
        { 
            new BigInteger(s2);
            System.out.println(s2 + " is a valid BigInteger"); 
        }  
        catch (NumberFormatException e) 
        { 
            System.out.println(s2 + " is not a valid BigInteger");
            System.out.println(e);
        } 
        
        try 
        { 
            new BigInteger(s3);
            System.out.println(s3 + " is a valid BigInteger"); 
        }  
        catch (NumberFormatException e) 
        { 
            System.out.println(s3 + " is not a valid BigInteger");
            System.out.println(e);
        } 
    }
}



/*
run:

8217528938039999999999982734590087211199382724324131999999999372732342342928727231421289 is a valid BigInteger
99999999999999999999999289380398273459009393837372827846462323998923842908472984729839199999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999990982374121 is a valid BigInteger
821752893803999999999998273459008721119938272432413e500 is not a valid BigInteger
java.lang.NumberFormatException: For input string: "32413e500"

*/

 

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