How to generate 3 digits random numbers in C#

1 Answer

0 votes
using System;
using System.Text;

class Program
{
    static void Main()
    {
        Random rand = new Random(); 
  
        for (int i = 1; i <= 50; i++) { 
            Console.WriteLine(rand.Next(100, 1000)); 
        } 
    }
}
 
 
 
/*
 
run:
 
969
324
241
716
247
792
730
477
382
272
264
196
458
462
677
745
360
951
604
807
837
224
512
216
804
215
522
488
629
931
792
723
839
574
198
913
792
823
693
211
768
450
225
963
605
716
658
810
516
988
 
*/

 



answered Jun 18, 2019 by avibootz

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